C语言中的运算符|S1(算术运算符)

2021年4月25日17:31:22 发表评论 958 次浏览

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C语言中的运算符|S1(算术运算符)1

运算符是任何编程语言的基础。因此, 如果不使用运算符, C语言的功能是不完整的。运算符允许我们对操作数执行不同类型的运算。在C中, 可以将操作符归类为以下类别:

  • 算术运算符s(+, -, *, /, %, 后递增, 前递增, 后递减, 前递减)
  • 关系运算符(==, !=, >, <, > =&<=)逻辑运算符(&&, ||和!)
  • 按位运算符(&, |, ^, ~, >>和<<)
  • 赋值运算符s(=, + =, -=, * =等)
  • 其他运营商(条件, 逗号, sizeof, 地址, 重定向)

算术运算符:这些用于对操作数执行算术/数学运算。属于此类的二进制运算符是:

  • 加成:的‘+’运算符将两个操作数相加。例如, x + y.
  • 减法:的‘-’运算符减去两个操作数。例如, 设.
  • 乘法:的‘*’运算符将两个操作数相乘。例如, x * y.
  • 师:的‘/’运算符将第一个操作数除以第二个。例如, x / y.
  • 模量:的‘%’当第一个操作数除以第二个操作数时, 运算符将返回余数。例如, x%y.

C

//C program to demonstrate working of binary arithmetic operators
#include <stdio.h>
  
int main()
{
     int a = 10, b = 4, res;
  
     //printing a and b
     printf ( "a is %d and b is %d\n" , a, b);
  
     res = a + b; //addition
     printf ( "a+b is %d\n" , res);
  
     res = a - b; //subtraction
     printf ( "a-b is %d\n" , res);
  
     res = a * b; //multiplication
     printf ( "a*b is %d\n" , res);
  
     res = a /b; //division
     printf ( "a/b is %d\n" , res);
  
     res = a % b; //modulus
     printf ( "a%b is %d\n" , res);
  
     return 0;
}

C ++

#include <iostream>
using namespace std;
  
int main() {
     int a = 10, b = 4, res; 
  
     //printing a and b 
     cout<<"a is " <<a<<" and b is " <<b<<"\n" ; 
  
     //addition
     res = a + b;  
     cout <<"a+b is: " <<res <<"\n" ; 
  
     //subtraction
     res = a - b;  
     cout <<"a-b is: " <<res <<"\n" ; 
      
     //multiplication
     res = a * b;  
     cout <<"a*b is: " <<res <<"\n" ; 
      
     //division 
     res = a /b; 
     cout <<"a/b is: " <<res <<"\n" ; 
      
     //modulus 
     res = a % b; 
     cout <<"a%b is: " <<res <<"\n" ; 
  
     return 0;
}

输出如下:

a is 10 and b is: 4
a+b is: 14
a-b is: 6
a*b is: 40
a/b is: 2
a%b is: 2

属于一元算术运算符类别的是:

  • 增量:的‘++’运算符用于递增整数值。当放置在变量名称(也称为预增量运算符)之前时, 其值会立即增加。例如, ++ x.
    当将其放在变量名之后(也称为后递增运算符)时, 其值将暂时保留, 直到执行该语句为止, 并且在下一个语句执行之前对其进行更新。例如, x ++.
  • 减量:的‘– –’运算符用于减少整数值。当放置在变量名称(也称为预减运算符)之前时, 其值将立即减小。例如, - - X.
    当将其放在变量名(也称为后减运算符)之后时, 其值将暂时保留, 直到执行该语句为止, 并且在下一个语句执行之前对其进行更新。例如, X - -.

C

//C program to demonstrate working of Unary arithmetic operators
#include <stdio.h>
  
int main()
{
     int a = 10, b = 4, res;
  
     //post-increment example:
     //res is assigned 10 only, a is not updated yet
     res = a++;
     printf ( "a is %d and res is %d\n" , a, res); //a becomes 11 now
  
     //post-decrement example:
     //res is assigned 11 only, a is not updated yet
     res = a--;
     printf ( "a is %d and res is %d\n" , a, res); //a becomes 10 now
  
     //pre-increment example:
     //res is assigned 11 now since a is updated here itself
     res = ++a;
     //a and res have same values = 11
     printf ( "a is %d and res is %d\n" , a, res);
  
     //pre-decrement example:
     //res is assigned 10 only since a is updated here itself
     res = --a;
     //a and res have same values = 10
     printf ( "a is %d and res is %d\n" , a, res);
  
     return 0;
}

C ++

#include <iostream>
using namespace std;
  
int main() {
     int a = 10, b = 4, res;
  
     //post-increment example:
     //res is assigned 10 only, a is not updated yet
     res = a++;
     //a becomes 11 now
     cout <<"a is " <<a<<" and res is " <<res<<"\n" ; 
  
     //post-decrement example:
     //res is assigned 11 only, a is not updated yet
     res = a--;
     //a becomes 10 now
     cout <<"a is " <<a<<" and res is " <<res<<"\n" ;
  
     //pre-increment example:
     //res is assigned 11 now since a is updated here itself
     res = ++a;
     //a and res have same values = 11
     cout <<"a is " <<a<<" and res is " <<res<<"\n" ;
  
     //pre-decrement example:
     //res is assigned 10 only since a is updated here itself
     res = --a;
     //a and res have same values = 10
     cout <<"a is " <<a<<" and res is " <<res<<"\n" ;
  
     return 0;
}

输出如下:

a is 11 and res is 10
a is 10 and res is 11
a is 11 and res is 11
a is 10 and res is 10

我们很快将在不同职位上讨论其他类别的运营商。

要知道运算符优先级和关联性, 请参阅这个链接:

C语言中的运算符测验

本文由Ayush Jaggi贡献。如果发现任何不正确的地方, 或者你想分享有关上述主题的更多信息, 请发表评论

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