如何使用JavaScript检查元素是否是父元素的子元素?

2021年3月29日18:20:57 发表评论 94 次浏览

方法1:使用Node.contains()方法

Node.contains()方法用于检查给定节点是否是任何级别的另一个节点的后代。后代可以直接是子元素父元素, 也可以是子元素的父元素。它返回结果的布尔值。

在父元素上使用此方法, 并且在该方法中传递的参数是要检查的子元素。如果子元素是父元素的后代, 则返回true。这意味着该元素是父级的子级。

语法如下:

function checkParent(parent, child) {
     if (parent.contains(child))
         return true ;
         return false ;
}

例子:

< html >
  
< head >
     < title >
         How to Check if an element is a 
       child of a parent using JavaScript?
     </ title >
     < style >
         .parent, .child, .non-child {
             border: 2px solid;
             padding: 5px;
             margin: 5px;
         }
     </ style >
</ head >
  
< body >
     < h1 style = "color: green" >lsbin</ h1 >
     < b >
       How to Check if an element is
       a child of a parent using JavaScript?
     </ b >
     < div class = "parent" >This is the parent div.
         < div class = "child" >This is the child div.
         </ div >
     </ div >
     < div class = "non-child" >
         This is outside the parent div.
     </ div >
     < p >Click on the button to check if the 
       elements are child of a parent.</ p >
     < p >Child has parent:
         < span class = "output-child" ></ span >
     </ p >
     < p >Non-Child has parent:
         < span class = "output-non-child" ></ span >
     </ p >
  
     < button onclick = "checkElements()" >
         Check elements
     </ button >
     < script >
         function checkParent(parent, child) {
             if (parent.contains(child))
                 return true;
             return false;
         }
  
         function checkElements() {
             parent = document.querySelector('.parent');
             child = document.querySelector('.child');
             non_child = document.querySelector('.non-child');
  
             output_child = checkParent(parent, child);
             output_non_child = checkParent(parent, non_child);
  
             document.querySelector('.output-child').textContent =
                 output_child;
             document.querySelector('.output-non-child').textContent =
                 output_non_child;
         }
     </ script >
</ body >
  
</ html >

输出如下:

在单击按钮之前:

包含之前

单击按钮后:

后包含

方法2:遍历给定子元素的父元素

通过不断地逐个元素地循环访问元素的父元素, 可以检查子元素是否具有给定的父元素。通过访问以下节点找到每个节点的父节点parentNode返回父节点(如果有)的属性。

使用while循环, 直到找到所需的父级或不再存在任何父级元素为止。在此循环内, 每次迭代中都会找到每个元素的父节点。如果父节点在任何迭代中都与给定节点匹配, 则意味着该元素是父节点的子节点。

语法如下:

function checkParent(parent, child) {
     let node = child.parentNode;
  
     // keep iterating unless null
     while (node != null ) {
         if (node == parent) {
             return true ;
         }
      node = node.parentNode;
      }
    return false ;
}

例子:

< html >
  
< head >
     < title >
         How to Check if an element is a 
       child of a parent using JavaScript?
     </ title >
     < style >
         .parent, .child, .non-child {
             border: 2px solid;
             padding: 5px;
             margin: 5px;
         }
     </ style >
</ head >
  
< body >
     < h1 style = "color: green" >lsbin</ h1 >
     < b >
       How to Check if an element is
       a child of a parent using JavaScript?
     </ b >
     < div class = "parent" >This is the parent div.
         < div class = "child" >This is the child div.
         </ div >
     </ div >
     < div class = "non-child" >
         This is outside the parent div.
     </ div >
     < p >Click on the button to check if 
       the elements are child of a parent.</ p >
     < p >Child has parent:
         < span class = "output-child" ></ span >
     </ p >
     < p >Non-Child has parent:
         < span class = "output-non-child" ></ span >
     </ p >
  
     < button onclick = "checkElements()" >
         Check elements
     </ button >
     < script >
         function checkParent(parent, child) {
             let node = child.parentNode;
  
             // keep iterating unless null
             while (node != null) {
                 if (node == parent) {
                     return true;
                 }
                 node = node.parentNode;
             }
             return false;
         }
  
         function checkElements() {
             parent = document.querySelector('.parent');
             child = document.querySelector('.child');
             non_child = document.querySelector('.non-child');
  
             output_child = checkParent(parent, child);
             output_non_child = checkParent(parent, non_child);
  
             document.querySelector('.output-child').textContent =
                 output_child;
             document.querySelector('.output-non-child').textContent =
                 output_non_child;
         }
     </ script >
</ body >
  
</ html >

输出如下:

在单击按钮之前:

前循环

单击按钮后:

循环后

木子山

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